1.47 litres of a gas is collected over water at 30°C and a barometric pressure of 744 mm. If the gas has a weighto
1.98 g and the vapour pressure of water at 30°C is 32 mm, what is the molecular weight of the gas?
plz give soln if anyone knows
plz help me
Answers
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Explanation:
Given
w = 1.98g
V = 1.47 litre
T = 303 K
P = 744 - 32 = 712mm = 712760 atm
Since For dry gas , PV=wmRT
=712760×1.47=1.98m×0.0821×303
∴m=35.76g
Hence answer is (c)
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