Question

[1÷4a-1÷2b 1]power 2

Answer 1

$\large\tt\red{Using\:identity}$

$\small\sf{{(x + y + z)}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2yz + 2zx}$

$\small\sf{{( \frac{1}{4}a) }^{2} + {( \frac{1}{2}) b}^{2} + {(1)}^{2} + 2( \frac{1}{4})( - \frac{1 }{2} ) + 2( - \frac{1}{2} )(1) + 2(1)( \frac{1}{4} )}$

$\small\sf{ \frac{1}{16} {a}^{2} + \frac{1}{4} {b}^{2} + 1 - \frac{1}{4} ab - b + \frac{1}{2} a}$

$\small\sf{\frac{ {a}^{2} }{16} + \frac{ {b}^{2} }{4} + 1 - \frac{ab}{4} - b + \frac{a}{2}}$