1+4cosec^2A×Cot^A what is the whole square of it
Answers
Answered by
0
Heya,
1 + 4Cosec²A*Cot²A
= 1 + 4/sin²A*sin²A/cos²A
= 1 + 4/cos²A
= 1 + 4sec²A
Squaring the result gives us,
(1 + 4sec²A) = 1 + 16sec⁴A + 8sec²A
Hope this helps you....:)
1 + 4Cosec²A*Cot²A
= 1 + 4/sin²A*sin²A/cos²A
= 1 + 4/cos²A
= 1 + 4sec²A
Squaring the result gives us,
(1 + 4sec²A) = 1 + 16sec⁴A + 8sec²A
Hope this helps you....:)
Similar questions