1.4g of hydrocarbon on combustion gave ratio 1.8g water.the empirical formula is
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If sub-atomic / molecular formula will be Cx Hy 1.8 g of water equivalents to 0.1 mole of water equivalents to 0.2 moles of Hydrogen atom. Presently , Hydrogen atom is originating from hydrocarbon so 'no. of moles of hydrocarbon × y=0.2'
=》(1.4/(12 × X + 1 × y )) × y = 0.2.
O n solving, we get
y/x = 2.
Thus, empirical formula is CH2.
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Answer:
CH2
Explanation:
The formula to calculate the percentage of hydrogen present is 2/18×wt of h2o formed/wt of organic compound×100
by substituting these values qe get 14%
- when we correlate the obtained hydrogen percentage with the given compounds we get CH2 as answer
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