Question

1. (4x²-5x+7)- (3x² + 2x + 1) + (x² +x-5) या बहुपदींना सरळरूप दिले असता कोणती
बहुपदी मिळेल?
(1) 2x2 - 8x -1 (2) 2x2 - 6x +1 (3) 2x2 -1 (4) 6x-1.​

Answer 1

Step-by-step explanation:

$(4 {x}^{2} - 5x + 7) - (3 {x}^{2} + 2x + 1) + ( {x}^{2} + x - 5) \\ = 4 {x}^{2} - 5x + 7 - 3 {x}^{2} - 2x - 1 + {x}^{2} + x - 5 \\ = 4 {x}^{2} - 3 {x}^{2} + {x}^{2} - 5x - 2x + x + 7 - 1 - 5 \\ = 2 {x}^{2} - 6x + 1$

option (2) is correct answer

Hope you get your answer

Answer 2

Answer:

abhi jyada aage tk nhi gyi .. exam hai mere isliye ..aap btao kaise hai ..