Math, asked by divyarc84, 9 months ago

(1)
4x2 +9y2 + 16z2 + 12xy-24yz-16xz​

Answers

Answered by REDPLANET
5

Answer:

Using identity

a² + b² + c² + 2ab - 2bc - 2ca = (a + b - c)²

= 4x² +9y² + 16z² + 12xy - 24yz - 16xz​

= (2x)² + (3y)² + (-4z)² + 2(2x)(3y) + 2(3y)(-4z) + 2(-4z)(2x)​

= (2x + 3y -4z)²

HOPE THIS HELPS YOU.........

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Answered by 6954treesa
1

Answer:

4x2 + 9y2 + 16z2 + 12xy – 24yz – 16xz

= (2x)2 + (3y)2 + (- 4z)2 + 2 (2x) (3y) + 2 (3y) (- 4z) + 2 (- 4z) (2x)

= (2x + 3y – 4z)2 = (2x + 3y + 4z) (2x + 3y – 4z)

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