Math, asked by mjanghu504, 10 hours ago

1 - 4y^3-3 √2y+3
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Answers

Answered by sehgalp381
20

Answer:

1 -  4y {}^{3}  - 3 \sqrt{2} y + 3 \\ 1 -  64y {}^{3}  - 18y + 3 \\  1 - 3 - 64y {}^{3}  - 18y \\  - 2 - 64y {}^{3}  - 18y \\  - 64y {}^{3}  - 18y - 2

Step-by-step explanation:

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