Question

1.5.1 Rationalising the
Can we
What is
ABFLJM
How do we find the value? A
$3 + \sqrt{2}$
​

Answer 1

Answer:

The given fraction is

6

−

5

1

To rationalize the denominator we can multiply both numerator and denominator by

6

+

5

(the conjuate of

6

−

5

)

∴

6

−

5

1

=

(

6

−

5

)(

6

+

5

)

1×(

6

+

5

)

=

(

6

)

2

−(

5

)

2

6

+

5

....((a−b)(a+b)=a

2

−b

2

)

=

6−5

6

+

5

=

1

6

+

5

=

6

+

5

Now, comparing

6

+

5

with

a

+

5

,

we get the value of 'a' as 6.

Step-by-step explanation:

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