Question

(1/5+2/5i)-(4+5/2i) =a+bi then b=
a)-19/5
b)-21/10
c)19/5
d)21/10​

Answer 1

$\bold {\huge {\mathfrak{Hello!}}}$

$\bold{( \frac{1}{5} + i\frac{2}{5} ) - (4 + i\frac{5}{2} )}$

$\longrightarrow \frac{1}{5} - 4 + i \frac{2}{5} - i\frac{5}{2}$

$\longrightarrow - \frac{19}{5} + (- i \frac{21}{10} )$

Hance, b=-21/10

$\huge \bold{\boxed {\mathtt{Option \: B}}}$