Math, asked by manojkumar27173, 2 months ago

1/√5+,√3-2√2 rationalise the denominater​

Answers

Answered by subhamn390
0

Step-by-step explanation:

  1. 1/√5=1*√5/√5*√5=1√5/√25=√5/5

this is the answer for first one.

now in second one,

  1. √3-2√2=√3-2√2/1=√3-2√2*√3+2√2/1*√3+2√2
  2. now,√3^2-2√2^2/√3+2√2=√9-√64/√3+√8=3-8/√3+√8=-5/√3+√8

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