Question

1. – 5 + ____ = - 5 .

2. – 17 / 19 x ____ = 1.

3. Additive inverse of - 8 / 3 is _____.

4. Multiplicative identity is ____.

II. Answer the following questions. 6M.

5. Simplify 2 / 5 + 3 / 7 + (- 6 / 5) + (-13 / 7).

6. Verify that 2 / 3 x [ 5 /6 + 7 / 8] = [ 2 / 3 x 5 / 6] + [ 2 / 3 x 7 / 8].

7. Multiply the reciprocals of - 2 / 3 and 5 / 6.

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Answer 1

Step-by-step explanation:

1. – 5 + 0 = - 5 .

2. – 17 / 19 x $\frac{-19}{17}$ = 1.

3. Additive inverse of - 8 / 3 is $\frac{8}{3}$.

4. Multiplicative identity is 1.

II. Answer the following questions. 6M.

5. Simplify 2 / 5 + 3 / 7 + (- 6 / 5) + (-13 / 7).

         $\frac{2}{5} + \frac{3}{7} + \frac{-6}{5} + \frac{-13}{7}$

       =  $\frac{14 + 15 - 42 - 65}{35}$

        =  $\frac{-78}{35}$

6. Verify that 2 / 3 x [ 5 /6 + 7 / 8] = [ 2 / 3 x 5 / 6] + [ 2 / 3 x 7 / 8].

     LHS = $\frac{2}{3} * [ \frac{5}{6} + \frac{7}{8} ]$ = $\frac{2}{3} * [\frac{20 + 21}{24} ]$ = $\frac{2}{3} * \frac{41}{24}$ = $\frac{41}{36}$

     RHS = $[\frac{2}{3} * \frac{5}{6} ] + [\frac{2}{3} * \frac{7}{8} ]$ = $\frac{5}{9} + \frac{7}{12}$ = $\frac{20 + 21}{36}$ = $\frac{41}{36}$

     LHS = RHS

   Hence verified.

7. Multiply the reciprocals of - 2 / 3 and 5 / 6.

    Reciprocal of $\frac{-2}{3} = \frac{-3}{2}$

    Reciprocal of $\frac{5}{6} = \frac{6}{5}$

     $\frac{-3}{2} * \frac{6}{5}$  =  $\frac{-9}{5}$

Answer 2

Answer:

-5+0 = -5

-17/19×-19/17 = 1

8/3