Question

(1/5)‐⁸ × (1/5)‐⁴ = (1/5)‐4x​

Answer 1

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$\longmapsto \sf \bigg\lgroup \frac{1}{5} {\bigg \rgroup}^{ - 8} \times \bigg\lgroup \frac{1}{5} {\bigg \rgroup}^{ - 4} =\bigg\lgroup \frac{1}{5} {\bigg \rgroup}^{ -4x}$

$\longmapsto \sf \bigg\lgroup \frac{1}{5} {\bigg \rgroup}^{ - 8 - 4} =\bigg\lgroup \frac{1}{5} {\bigg \rgroup}^{ -4x}$

$\longmapsto \sf \bigg\lgroup \frac{1}{5} {\bigg \rgroup}^{ -12} =\bigg\lgroup \frac{1}{5} {\bigg \rgroup}^{ -4x}$

$\longmapsto \sf - 12 = - 4x$

$\longmapsto \sf x = \frac{ - 12}{ - 4}$

$\longmapsto \boxed{ \sf x = 3}$

Answer 2

Answer:

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Step-by-step explanation:

ur answer is there in image