1,5,9,13...is an A.P find tn and Sn also find t20 and S100?
Answers
Answered by
0
Step-by-step explanation:
Here first term a=
6
1
and common difference d=
4
1
−
6
1
=
12
1
.
Now, t
20
=a+19d⇒t
20
=
6
1
+19×
12
1
=
12
21
=
4
7
Also S
10
=
2
10
[2a+(10−1)d]
⇒S
10
=5[2×
6
1
+9×
12
1
]=5[
3
1
+
4
3
]=
12
65
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