(1.) 5 buses carry 325 passengers. How many passengers can be carried by 8 such buses?
(2.)Finishes his work in 15 days while “B” takes 10 days. How many days will the same
work be done if they work together?
(3.)The cost of 9 liters of petrol is Rs.378. How much will 15 liters of petrol cost?
(4.)12 workers finish a job in 20 hours How many workers will be required to finish the sam
work in 15 hours?
solve it
Answers
Step-by-step explanation:
1. 5buses carry=325passengers
1 buses carry=325/5
=65passengers
8buses carry=65×8
520passsengers
2. A takes no.of days for a work=15days
B takes no.of days for a work=10days
they together take no.of days=5days
3. 9 litres petrol=rs378
1 litres petrol=378/9
=rs42
15litres petrol=15×42
=rs630
4. 12 workers complete a work=20hours
1 worker complete a work =20/12
=20×60/12
=1200/12
=100 min or 1hr40min
15 hours =900min
that means in 15 hours they required 9 workers
Answer:
1. 520
2. 6 Days
3. 630
4. 25
Step-by-step explanation:
1. 325/5 = 65
65 x 8
2. LCM of 15 & 10 = 30
HCF of 15 & 10 = 5
30/5 = 6
3. 378/9 = 42
42 x 15 = 630
4. 20/12 = 1.6
1.6 x 15 = 25