Math, asked by kiransingh1186, 1 month ago

(1.) 5 buses carry 325 passengers. How many passengers can be carried by 8 such buses?

(2.)Finishes his work in 15 days while “B” takes 10 days. How many days will the same
work be done if they work together?

(3.)The cost of 9 liters of petrol is Rs.378. How much will 15 liters of petrol cost?

(4.)12 workers finish a job in 20 hours How many workers will be required to finish the sam
work in 15 hours?
solve it​

Answers

Answered by monikeshari1
1

Step-by-step explanation:

1. 5buses carry=325passengers

1 buses carry=325/5

=65passengers

8buses carry=65×8

520passsengers

2. A takes no.of days for a work=15days

B takes no.of days for a work=10days

they together take no.of days=5days

3. 9 litres petrol=rs378

1 litres petrol=378/9

=rs42

15litres petrol=15×42

=rs630

4. 12 workers complete a work=20hours

1 worker complete a work =20/12

=20×60/12

=1200/12

=100 min or 1hr40min

15 hours =900min

that means in 15 hours they required 9 workers

Answered by SmaranikaSahoo26
0

Answer:

1. 520

2. 6 Days

3. 630

4. 25

Step-by-step explanation:

1. 325/5 = 65

65 x 8

2. LCM of 15 & 10 = 30

HCF of 15 & 10 = 5

30/5 = 6

3. 378/9 = 42

42 x 15 = 630

4. 20/12 = 1.6

1.6 x 15 = 25

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