Question

1.5
Calculate the mass of sodium acetate (CHCOONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol!​

Answer 1

Explanation:

0.375 M solution of (CH3COONa) = 0.375 moles(grams) of (CH3COONa) dissolved in 1000 ml of solvent.

But according to question ,we have to make a 500 ml solution of (CH3COONa)

∴Number of moles of sodium acetate in 500 mL

0.375÷1000×500

0.1875 mole

Molar mass of sodium acetate = 82.0245 g mole–1 (Given)

∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)

= 15.38 g