В 1 5 From the given figure, find : (i) sin A (ii) cos C (iii) tan A (iv) cosec C (v) sec2A - tan-A. 13 A
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Step-by-step explanation:
sinA=
AC
BC
=
5
4
cosA=
AC
AB
=
5
3
cosA=
4/5
3/5
=
4
3
secC=
BC
AC
mm =
4
5
cscC=
AB
AC
=
3
5
tanC=
BC
AB
=
4
3
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