Question

1
5. If tan(A+B)= 13 and tan(A-B)=1/√3 ; 0° < (A+B) ≤90°; A≥B, Find ‘A’and “B”.
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Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

RIGHT QUESTION:

tan (A + B) = √3 and tan (A – B) = 1/√3 0° < A + B ≤ 90°; A > B. find A and B.

SOLUTION :

tan (A + B) = √3 ⇒ A + B = 60° ………….. (i)

tan (A – B) = 1/√3 ⇒ A – B = 30° ………… (ii)

From Eq. (i) + Eq.(ii), we have

2A = 90 ⇒ = 45°

A= 45°

From eq. (i), A + B = 60°

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. (i), A + B = 60°

45° + B = 60°

∴ B = 15