(1,5) Is a solution of _____
(a) 2x-3y+4=0 (b) x+y=8 (c)
2x+5y=20 (d) 2x+y=7
Answers
(d) 2x+y=7
= 2(1)+5
=2+5
=7=7
Answer:
d)2x+y=7
Step-by-step explanation:
Given:-
Point (1,5)
To find:-
(1,5) is a solution of the following equations
(a) 2x-3y+4=0 (b) x+y=8 (c)
2x+5y=20 (d) 2x+y=7
Solution:-
Given point = (1,5)
a)2x+3y+4=0
on Substituting the values of x = 1 and y=5 then
LHS=2x+3y+4
=>2(1)+3(5)+4
=>2+15+4
=>21
RHS = 0
LHS ≠RHS
(1,5) is not a solution of 2x+3y+4 =0
_________________________________
b) Given equation is x+y=8
on Substituting the values of x = 1 and y=5 then
LHS = x+y
=>1+5
=>6
RHS = 8
LHS≠RHS
(1,5) is not a solution of x+y = 8
___________________________________
c)Given equation is 2x+5y=20
on Substituting the values of x = 1 and y=5 then
LHS = 2x+5y
=>2(1)+5(5)
=>2+25
=>27
RHS = 20
LHS ≠RHS
(1,5) is not a solution of 2x+5y=20
__________________________________
d)Given equation is 2x+y=7
on Substituting the values of x = 1 and y=5 then
LHS= 2x+y
=>2(1)+5
=>2+5
=>7
RHS =7
LHS = RHS
1,5) is a solution of 2x+y=7
_________________________________
Answer:-
(1,5) is a solution of 2x+y = 7
Used Concept:-
Solution:-
Any pair of values of x and y which satisfy ax+by+c = 0 is called the solution of the linear equation.
Satisfy means LHS = RHS