1.5 kg of a gas
at a pressure of a bar in
expanded adiabetically to a pressure of 2
bar . Find the work done during expansion
and change
in internal
energy if the initial temperature
of the gas
is 350°C
Answers
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Explanation:
Given PV
1.5
=constant
⇒P
1
V
1
1.5
=P
2
V
2
1.5
P
2
=P
1
(
V
2
V
1
)
1.5
=3×10
5
(
0.2
0.1
)
1.5
=1.06×10
5
Pa
Work done is given by
W=
1−n
P
2
V
2
−P
1
V
1
=
1−1.5
(1.06×10
5
)(0.2)−(3×10
5
)(0.1)
=17.6 kJ
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