Question

1.5 kg of liquid having a constant specific heat of 2.5 kJ/kg K is heated in
a well-insulated chamber causing the temperature to rise by 13 K. Find
AE and W for the process.​

Answer 1

Arunesh kumar from kannauj and ME second year in

Answer 2

Answer:

The value of $\Delta E$ and $W$ for the process is $\Delta \mathrm{E}=56.25 \mathrm{~kJ},$

$\mathrm{~W}=-56.25 \mathrm{~kJ}$

Explanation:

Most systems' heat capacity is variable, depending on factors such as pressure, volume, and temperature.

The amount of heat required to increase the temperature of one gramme of any substance by one degree Celsius is known as specific heat.

Given = constant heat is $2.5 kJ/kg$

$t=13k$

Here in the sysytem Heat is added$=1.5 \times 2.5 \times 15 \mathrm{~kJ}$

$=56.25 \mathrm{~kJ}$

$\therefore \quad \Delta$ E rise $=56.25 \mathrm{~kJ}$

The insulated then we will have  $\Delta Q=0$

$\begin{aligned}\therefore & \Delta Q &=\Delta \mathrm{E}+\mathrm{W} \\\text { } & 0 &=56.25+\mathrm{W} \\\text { } & \mathrm{W} &=-56.25 \mathrm{~kJ}\end{aligned}$