)1.5 L of N2 at 25 deg Celsius and 700 mm Hg pressure
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Calculate the volume occupied by 4.045×10
23
molecules of oxygen at 27
∘
C and having a pressure of 700 torr.
Medium
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No. of moles
′
n
′
=
6.023×10
23
4.045×10
23
=0.672
P=
760
700
atm
Now using the gas equation, PV=nRT
=
760
700
V=0.672×0.0821×300
⟹V=17.97 dm3
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