Question

1.5 m tall man stands at a distance from a lamp post of 6 m height and Casts a shadow of 3 M find the distance between him and the lamp post​

Answer 1

Let AB be boy = 1.5m

CD be lamp = Let it be x m.

OB be shadow cast by boy = 4.5m

BD be distance between boy and lamp = 3m

Therefore

In ΔAOB,

=> tan θ = AB/OB

In ΔCOD,

=> tan θ = CD/OD = CD/(OB+BD)

∴ AB/OB = CD/(OB+BD)

=> 1.5/4.5 = CD/(4.5+3)

=> CD = 7.5/3 = 2.5m

Answer 2

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