Physics, asked by kunwarmanhas87255, 9 months ago

1
5 The electric field due to a charge at a distance of 3 m from it
is 500 NC- The magnitude of the charge is
9x10° N-m?/C?
41
(a) 2.5 uc
(b) 2.0 ud
(c) 1.0 uc
(d) 0.5uC

Answers

Answered by pushpa9801019299
0

Answer:

I don't know the answer dude but another know that answer please follow up

Answered by imraushanraaz
1

Explanation:

The electric field due to a charge at a distance of 3 m from it is 500NC−1. The magnitude of the charge is

[14πε0=9×109N−m2/C2]

answer=0.5uC (d)

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