1.50 kg K3C6H5O7 to moles?
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Answer:
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Explanation:
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The compound K3C6H5O7 is Potassium Citrate.
=> K = 39 , C = 12 , H = 1, O = 16.
It has a molar mass = 39 x 3 + 6 x 12 + 5 x 1 + 7 x 16 =>117+72+5+112
=> 306 grams per mole.
So, 1.5 kg is 1500 g.
So, 1500 g is 1500/306 moles => 4.902 moles (approx.)
Hence, the number of moles in 1.5 kg of anhydrous Potassium Citrate is 4.902 moles.
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