Question

1.505 × 10^23 atoms of C​

Answer 1

1mole=6.022×10  

23

(N  

a

​

=Avogadro  

′

snumber)

Thenumberofmoles=  

Avogadro  

′

snumber

Givennumberofmolecules

​

 

Numberofmoles=  

6.022×10  

23

 

1.0505×10  

23

 

​

 

Number of moles =0.17

Now, to calculate mass, apply the formula:

Numberofmoles(n)=  

Molarmass(M)

Mass(m)

​

 

We can write:

Mass (m) = Number of moles (n) × Molar mass of CO  

2

​

(M)

Mass=0.17mol×44g/mol

Mass=7.48g

Thus, the mass of 1.0505×10  

23

 molecule of CO  

2

​

 is 7.48g.

Answer 2

Answer:

1 mol

=

6.022

×

10

23

molecules

Moles of

CO

2

present in sample

1.505

×

10

23

molecules

×

1 mol

6.022

×

10

23

molecules

=

0.25 mol

Molar mass of

CO

2

is

44 g/mol

. Mass of

0.25 mol

of

CO

2

is