1.51. А 3 2 resistor having 2 A current will
dissipate the power of
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Answer:
128W
Explanation:
If you meant a 32Ω resistor, the answer is 128W.
It's just direct formula application.
P = I^2R
We have I as 2 A, R as 32Ω and hence power would be
2^2 x 32 = 4x32 = 128W
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