1.52 grams of the hydroxide of a metal on ignition gave 0.995 gms of oxide.The eq.mass of metal is
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Explanation:
mass of metal hydroxide/mass of metal oxide
= (eq.wt of metal + eq.wt of OH- )/eq.wt of metal + eq.wt of 0-²
= 1.52/0.995 = x + 17/x+8
x = 9
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