Question

(1.5b+1.2c)²+(1.5b+1.2c)²​

Answer 1

Step-by-step explanation:

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Answer 2

Given binomial:

$(1.5b+1.2c)^{2} +(1.5b+1.2c)^{2}$.

Here, two terms are same. So, we can write the given expression as $2\times (1.5b+1.2c)^{2}$.

Let us convert from decimal form to fractions in the above expression.

$=2\times[ \frac{3}{2}b+ \frac{6}{5}c]^{2}$

Applying the formula, $(a+b)^{2} =a^{2} +2ab+b^{2}$:

$=2\times[ (\frac{3}{2}b)^{2} +(2\times \frac{3}{2} \times \frac{6}{5})+( \frac{6}{5}c)^{2} ]$

$=2\times[ \frac{9}{4}b^{2} + \frac{18}{5}+ \frac{36}{25}c^{2} ]$

$=( \frac{9}{4}b^{2}\times2) + (\frac{18}{5}\times2)+ (\frac{36}{25}c^{2} \times2)$

$=\frac{9}{2}b^{2} + \frac{36}{5}+ \frac{72}{25}c^{2}$

The decimal form of the above expression is: $4.5b^{2} +7.2+2.88c^{2}$.

Hence, The simplified form of $(1.5b+1.2c)^{2} +(1.5b+1.2c)^{2}$ is $4.5b^{2} +7.2+2.88c^{2}$.