1.5g of CdCl2 was found to contain 0.9 g of CD.calculate the atomic weight of Cd
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percentage of cl2 in cdcl2 = 0.9÷1.5×100=100
therefore%of cl2in cdcl2 =100-60=40%
40% part (cl2) has at atomic weight
=2×35.5=71
60% part (cd) has at atomic weight
71×60÷40=106.5
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