Question

1.5x+0.1y=6.2;3x-0.4y=11.2 SOLVE USING METHOD using SUBSTITUTION method

Answer 1

Answer:

So, our solution is (x, y) = (3, 2)

Step-by-step explanation:

Given that

1.5x + 0.1y = 6.2 ......(1

3x - 0.4y = 11.2 .......(2

Multiplying equation (1) by 2 on both sides, we get

3x + 0.2y = 12.4 .....(3

From equation (2)

3x = 11.2 + 0.4y .....(4

Now, substitute the value of 3x from equation (4) into equation (3)

11.2 + 0.4y + 0.2y = 12.4

0.6y = 12.4 - 11.2

0.6y = 1.2

y = 1.2÷0.6

y = 2

Now, substitute the value of y into equation (4)

3x = 11.2 + 0.4 (2)

3x = 11.2 + 0.8

3x = 12

x = 12÷3

x = 4

So, our solution is (x, y) = (3, 2)

Answer 2

➡️Answer: (x = 4,y = 2)

➡️Solution:

Substitution Method

$1.5x + 0.1y = 6.2 \\ \\ 0.1y = 6.2 - 1.5x \\ \\ y = \frac{6.2 - 1.5x}{0.1} \\ \\ 3x - 0.4y = 11.2 \\ \\ put \: the \: value \: of \: y \: in \: second \: eq \\ \\ 3x - 0.4 (\frac{6.2 - 1.5x}{0.1}) = 11.2 \\ \\ 3x - 4(6.2 - 1.5x) = 11.2 \\ \\ 3x - 24.8 + 6x = 11.2 \\ \\ 9x = 11.2 + 24.8 \\ \\ 9x = 36 \\ \\ x = 4$
Now put the value of x in any one of the given equation

$1.5( 4) + 0.1y = 6.2 \\ \\ 6 + 0.1y = 6.2 \\ \\ 0.1y = 6.2 - 6 \\ \\ 0.1y = 0.2 \\ \\ y = \frac{ 0.2}{0.1} \\ \\ y = 2$
Hope it helps you