Math, asked by tabbharmal9746, 9 months ago

1/5x – 1/3y = 30, when y = 15?

Answers

Answered by prittishsak2014
0

Answer:

x=9/1351

Step-by-step explanation:

1/5x - 1/3y=30

1/5x- 1/3×15=30 since y=15

1/5x- 1/45=30

1/5x=30+1/45

1/5x=1351/45

1/x=(1351/45)×5

1/x=(1351/9)

therefore x=9/1351

Answered by lalankumar99395
1

Answer:

5)x-(2/3)y=30, where y=15

(1/5)x-(2/3)15=30

(1/5)x-(30/3)=30

x/5–10=30

x/5-(10–10)=30+10

x/5–0=40

x/5=40

(x/5)5=(40)5

x=

200

Or,

1/(5x)-2/(3y)=30, where y=15

1/(5x)-2/(3×15)=30

1/(5x)-2/(45)=30 (Multiply all terms by x to remove the independent variable x from the denominator)

x[1/(5x)-2/(45)=30]

1/5–2x/45=30x

(-2/45)x+1/5–30x=30x-30x

(-2/45)x—(1350/45)x+1/5=0

(-1352/45)x+1/5=0

(-1352/45)x+(1/5–1/5)=0–1/5

(-1352/45)x=-1/5

[(-1352/45)x](-45/1352)=-1/5(-45/1352) (Cancel the common factor 5 in the denominator and the numerator on the right side of the equation)

x=-1/1(-9/1352)

x=-(-9/1352)

x=

9/1352

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