Question

1/5x^2 +2x -15 factorize

Answer 1

Answer:

please refer to the attachment.

I hope it would help you

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Answer 2

Answer:

$\large p(x)=(\dfrac{1}{5}x+3)(x-5)$

$\large x=-15 \ or \ x=5$

Step-by-step explanation:

Given :

$\large p(x)=\dfrac{1}{5}x^2+2x-15$

By splitting mid term we get

$\large p(x)=\dfrac{1}{5}x^2+2x-15 \\\\\\\large p(x)=\dfrac{1}{5}x^2+3x-x-15 \\\\\\\large p(x)=x(\dfrac{1}{5}x+3)-5(\dfrac{1}{5}x+3)\\\\\\\large p(x)=(\dfrac{1}{5}x+3)(x-5)$

Zeroes of p ( x )

$\large p(x)=(\dfrac{1}{5}x+3)(x-5)=0\\\\\\\large (\dfrac{1}{5}x+3)=0 \ or \ (x-5)=0\\\\\\\large \dfrac{1}{5}x=-3 \ or \ x=5\\\\\\\large x=-15 \ or \ x=5$

Thus we factorize and get zeroes.