Question

1.5x+7y=17 ; 3x—2y=4
2.x—2y=—10 ; 3x—5y=—12


Please answer this question

Answer 1

Solution For 1:

Given,

$5x + 7y = 17 \\ = > x = \frac{17 - 7y}{5} \: \: \: \: \: \: \: \: \: \: \:........(i)$

$3x - 2y = 4$

On substituting Value of x

$3 \times \frac{17 - 7y}{5} - 2y = 4 \\ = > \frac{51 - 21y - 10y}{5} = 4 \\ = > 51 - 31y = 20 \\ = > 31 - 31y = 0 \\ = > 1 - y = 0 \\ = > y = 1$

Therefore,

$x = \frac{17 - 7 \times 1}{5} \\ = > x = 2$

Solution For 2:

Given,

$x - 2y = - 10 \\ = > x = 2y - 10$

$3x - 5y = - 12 \\ = > 3 \times (2y - 10) - 5y = - 12 \\ = > 6y - 30 - 5y = - 12 \\ = > y = 18$

Therefore,

$x = 2 \times 18 - 10 \\ = > x = 26$

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