Question

1/5x+y+2=0
y=1/3x-10
(substituition method)

Answer 1

Step-by-step explanation:

multiply equation 1 and 2 by 5 and 3

x+5y+10=0

3y=x-30

put x =3y+30

3y+30+5y+10=0

8y=-40

y=-5

put y=-5 in any equation

we get x=15

Answer 2

Answer:

• x= 15
• y= -5

Step-by-step explanation:

Given:

$\frac{1}{5}x + y + 2 = 0 \\ \: \: \: \: \: \: or \\ \frac{1}{5} x + y = - 2 = > \frac{x + 5y}{5} = - 2 \\ x + 5y = 5( - 2) = > x + 5y = - 10 \: \: \: \: \: ....(1) \\ \\ y = \frac{1}{3} x - 10 = > y = \frac{x - 30}{3} ....(2)$

putting value of y in eq.(1)

$= > x + 5y = - 10 \\ = > x + 5 ( \frac{x - 30}{3}) = - 10 \\ = > x + \frac{5x - 150}{3} = - 10 \\ = > 3x + 5x - 150 = 3( - 10) \\ = > 8x = - 30 + 150 \\ = > 8x = 120 \\ = > x = \frac{120}{8} \\ x = > 15$

Now, putting value of x in eq.(2)

$= > y = \frac{x - 30}{3} \\ = > 3(y) = 15 - 30 \\ = > 3y = - 15 \\ = > y = \frac{ - 15}{3} \\ y = > - 5$

Hence, the value of x is 15 and y is -5.