Math, asked by jayshreebachhaliya, 4 days ago

1+6÷3-(4+5)×7=

pls answer it fast

Answers

Answered by niteshrajputs995
1
  • As per the data given in the question, we have to determine the value of the given expression.

       Given data:- 1+6\div3-(4+5)\times7.

       To find:- the value of the given expression.

       Solution:-  

  • Here, we will use BODMAS RULE.  
  • BODMAS RULE:- It is a correct order to solve the mathematical expression.
  • Where, B stands for bracket
  • O stands for of
  • D stands for divide
  • M stands for multiplication
  • A stands for addition
  • S stands for subtraction.

    Therefore,

      =1+6\div3-(4+5)\times7\\=1+6\div3-9\times7\\=1+2-9\times7\\=1+2-63\\=3-63\\=-60.

Hence, the value will be -60.

Answered by aftabahemad
0

From the data given in the question, we have to determine the value of the unknown quantity in the given expression.

As per question,

It is  given that:- 1+6\div3-(4+5)\times7.

 So, for solving the expression, we will solve the above given expression by using BODMAS rule,

As we know that,

From BODMAS rule,

We have,

B stands for bracket

O stands for of

D stands for divide

M stands for multiplication

A stands for addition

S stands for subtraction.

So, applying the above concept,

We will get the answer as,

=1+6\div3-(4+5)\times7\\=1+6\div3-9\times7\\=1+2-9\times7\\=1+2-63\\=3-63\\=-60.

Hence, the value will be -60.

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