Question

1/6 (4y + 5) - 2/3 (2y + 7) = 3/2 solve and verify​

Answer 1

1/6 (4y + 5) - 2/3 (2y + 7) = 3/2

(4y + 5)/6 - (4y + 14)/3 = 3/2

2(4y + 5) - 4(4y + 14)/12 = 3/2

8y + 10 - 16y - 56/12 = 3/2

-8y - 46 = 3/2 * 12

-8y - 46 = 18

-8y = 18 + 46

-8y = 64

-y = 64/8

-y = 8

y = -8