Question

1/√6+√5 if √3=1.732,√5=2.236,√6=2.449 and √10=3.162

Answer 1

0.213 is the answer

hope ot helps

Answer 2

Answer:

Value of $\frac{1}{\sqrt{6}+\sqrt{5}}\:is\:0.213$

Step-by-step explanation:

To find: value of $\frac{1}{\sqrt{6}+\sqrt{5}}$

Consider,

$\frac{1}{\sqrt{6}+\sqrt{5}}$

$=\frac{1}{\sqrt{6}+\sqrt{5}}\times\frac{\sqrt{6}-\sqrt{5}}{\sqrt{6}-\sqrt{5}}$

$=\frac{\sqrt{6}-\sqrt{5}}{(\sqrt{6}-\sqrt{5})(\sqrt{6}+\sqrt{5})}$

using identity, ( x - y )( x + y ) = x ²- y²

$=\frac{\sqrt{6}-\sqrt{5}}{(\sqrt{6})^2-(\sqrt{5})^2}$

$=\frac{\sqrt{6}-\sqrt{5}}{6-5}$

$=\sqrt{6}-\sqrt{5}$

using value of √6 = 2.449 and √5 = 2.236

= 2.449 - 2.236

= 0.213

Therefore, Value of $\frac{1}{\sqrt{6}+\sqrt{5}}\:is\:0.213$