Question

√(1/6&(3 log⁡1728)/(1+1/2 log⁡〖0.36+1/3 log⁡8 〗 ))

Answer 1

Answer:

(1/6)√(3log1728)/(1+1/2log36+1/3log8)

=(1/6)√(3log(123)/(1+1/2log62+1/3log23) =

=(1/6)√(9log12)/(1+log6+log2)=

=(1/6)3√(log12)/(1+log12)=

=(1/2)√(log12)/(1+log12).

=√(log12)/(2+log144)