Question

1.6 g of sulphur was bornt in the air to form SO2 the number of molecules of SO2 introduced into the air will be

Answer 1

Answer:

3.011*10^22

Explanation:

S + O2 → SO2

1atom S will produce 1 molecule SO2

Molar mass S = 32g/mol

1.6g S = 1.6/32 = 0.05 mol S

This will contain 0.05*6.022*10^23 = 3.011*10^22 S atoms - which will produce 3.011*10^22 SO2 molecules.

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Answer 2

Answer:

3.011x10^22.

Explanation:

S+O2--->SO2

No. of moles of sulphur= 1.6/32=0.05

No.of moles of sulphur= No. of moles of SO2.

No.of molecules of SO2= 0.05x6.022x10^23.=3.011x10^22