Math, asked by rashmijagetiya3, 8 months ago

(1)
6. Test the divisibility of the following numbers by 7:
(i) 826
(in) 117
(iv) 6021
(v) 14126
(mm) 2345
(vi) 25368​

Answers

Answered by ABHINAVsingh56567
2

Answer:

To check if a number is evenly divisible by 7: Take the last digit of the number, double it Then subtract the result from the rest of the number If the resulting number is evenly divisible by 7, so is the original number.

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Step-by-step explanation:

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Answered by vedsatra7
6

Answer:

(i) 826 is divisible by 7.

We have 82 − 2 × 6 = 70, which is a multiple of 7.

(ii) 117 is not divisible by 7.

     We have 11 − 2 × 7 = −3, which is not a multiple of 7.

(iii) 2345 is divisible by 7.

We have  234 − 2 × 5 = 224, which is a multiple of 7.

(iv) 6021 is not divisible by 7.  

We have 602 − 2 × 1 = 600, which is not a multiple of  7.

(v)  14126 is divisible by 7.

   We have 1412 − 2 × 6 = 1400, which is a multiple of 7.

(vi)  25368 is divisible by 7.

     We have 2536 − 2 × 8 = 2520, which is a multiple of 7.

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