1.61gm Na2So4.10H2O contains same number of oxygen atom as present in x gram of H2SO4. Find x.
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Number of mole of Na₂SO₄.10H₂O = given weight/molecular weight
= 1.61 gm/(46 + 32 + 64 + 180)
= 1.61/322gm/mol
= 0.005
∵1 mole of Na₂SO₄.10H₂O contains 14 moles of Oxygen atoms
∴ 0.005 mole of Na₂SO₄.10H₂O contains 14 × 0.005 = 0.07 mole of oxygen atoms.
Now, number of moles of oxygen= weight/atomic weight
⇒0.07 × atomic weight = weight
⇒0.07 × 16 = weight
⇒ weight = 1.12g
Hence, answer is 1.12 g
= 1.61 gm/(46 + 32 + 64 + 180)
= 1.61/322gm/mol
= 0.005
∵1 mole of Na₂SO₄.10H₂O contains 14 moles of Oxygen atoms
∴ 0.005 mole of Na₂SO₄.10H₂O contains 14 × 0.005 = 0.07 mole of oxygen atoms.
Now, number of moles of oxygen= weight/atomic weight
⇒0.07 × atomic weight = weight
⇒0.07 × 16 = weight
⇒ weight = 1.12g
Hence, answer is 1.12 g
atharvananotkar:
The answer is incomplete as they had asked to find the wt of h2so4 not o2
They asked to find value of x . X is not other than weight of H2so4. Okay
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