(1/64)^0+(64)^-1/2-(-32)^4/5=?
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Answer:
9.
Step-by-step explanation:
(1/64)⁰+(64)^-1/2-(-32)^4/5
=1+(8²)^-1/2-(-2⁵)^4/5[any power 0=1]
=1+8^(2×-1/2)-(-2)^(5×4/5) [a power m whole power n = a^mn]
=1+8^-1+2⁴
=1-8+16 (8^-1=-8)
=9.
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