Math, asked by raotula, 5 months ago

(1/64)^0+(64)^-1/2-(-32)^4/5=?
Answer step by step with process.​

Answers

Answered by sireeshamachavarapu
1

Answer:

9.

Step-by-step explanation:

(1/64)⁰+(64)^-1/2-(-32)^4/5

=1+(8²)^-1/2-(-2⁵)^4/5[any power 0=1]

=1+8^(2×-1/2)-(-2)^(5×4/5) [a power m whole power n = a^mn]

=1+8^-1+2⁴

=1-8+16 (8^-1=-8)

=9.

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