Question

1-64a³
Factorise this question only who can ​

Answer 1

REFER TO THE ATTACHMENT FOR THE ANSWER

Answer 2

$1 - 64a^{3} \\= 1^{3} - (4a)^{3} \\= (1-4a)[ (1^{2} + 1\times (4a) + (4a)^{2}]$

$\boxed { \pink { a^{3} - b^{3} = (a-b)(a^{2}+ab+b^{2}}}$

$= ( 1 - 4a)( 1 + 4a + 16a^{2} )$

Therefore.,

$\red {1 - 64a^{3}}\green { = ( 1 - 4a)( 1 + 4a + 16a^{2} )}$

•••♪