1.68 g of Fe(s) react with 0.64 g oxygen and form FeO(s) and Fe2O3(s). If no reactant remain in reaction, select the incorrect statement about this reaction.
%(by mass) of Fe2O3 is more than 2 times of % (by mass) of FeO in final product
% (by mass) of Fe2O3 in product is more than 70%
O Mass of Fe2O3 in product is 1.60 g
Mass of FeO in product is 0.72 g
Answers
Answered by
5
Answer:
option 3 is the correct answer
Explanation:
O Mass of Fe2O3 in product is 1.60 g
Answered by
0
Answer:
Option 3rd
Explanation:
Among the various options given in question statement, the incorrect statement is the third one which is that
O Mass of Fe2O3 in product is 1.60 g
This statement is against the law of conservation of mass .
Law of conservation of mass states that the mass of reactants taking part in the reaction must be equal to the mass of the products produced in reaction.
If we have 0.64g of oxygen, then output cannot be more than this
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