Question

1/6sinx ,cosx ,tanx are in gp then the value of x

Answer 1

1/sinx , cosx , tanx are in GP
so,

cosx/(1/sinx) = tanx/(cosx)

sinx.cosx = sinx/cos²x

sinx( cos³x -1) = 0

but sinx ≠ 0 becoz in this way 1/sinx =∞
so, cos³x= 1

cosx = 1

x = 2nπ where n is integer number