Question

1,6x-3y+10=0
2,2x-y+9=0

Answer 1

hi mate,

solution: 1) 6x-3y+10=0

Such an equation is usually written y=mx+b

Calculate the Y-Intercept :

Notice that when x = 0 the value of y is 10/3 so this line "cuts" the y axis at y= 3.33333

y-intercept = 10/3 = 3.33333

Calculate the X-Intercept :

When y = 0 the value of x is -5/3 Our line therefore "cuts" the x axis at x=-1.66667

x-intercept = -10/6 = -5/3 = -1.66667

Slope = 2

x-intercept = -10/6 = -5/3 = -1.66667

y-intercept = 10/3 = 3.33333

2) 2x-y+9 = 0Calculate the Y-Intercept :

Notice that when x = 0 the value of y is 9/1 so this line "cuts" the y axis at y= 9.00000

y-intercept = 9/1 = 9.00000

Calculate the X-Intercept :

When y = 0 the value of x is -9/2 Our line therefore "cuts" the x axis at x=-4.50000

x-intercept = -9/2 = -4.50000

Slope = 2

x-intercept = -9/2 = -4.50000

y-intercept = 9/1 = 9.00000

i hope it helps you.

Answer 2

These are simultaneous equations

6x - 3y = -10    (i)

2x - y = -9       (ii)

Let's use elimination method (ii) ×3

6x - 3y = -10

-6x - 3y = -27

This equation is not solvable using this way. Sorry