Question

1/7×0.049 + 3/8- 7/20 simplify and express the result as a rational number in its lowest terms
​

Answer 1

Answer:

$\frac{4}{125}$ is the required lowest form

Step-by-step explanation:

I have simplified this expression step by step.

$\frac{1}{7}*0.049+\frac{3}{8}-\frac{7}{20}$

$=\frac{1}{7}*\frac{49}{1000}+\frac{3}{8}-\frac{7}{20}$

$=\frac{7}{1000}+\frac{3}{8}-\frac{7}{20}$

$=\frac{7}{1000}+\frac{3*125}{8*125}-\frac{7*50}{20*50}$

$=\frac{7}{1000}+\frac{375}{1000}-\frac{350}{1000}$

$=\frac{7+375-350}{1000}$

$=\frac{382-350}{1000}$

$=\frac{32}{1000}$

$=\frac{4}{125}$

Answer 2

Answer:

I have simplified this expression step by step.

\frac{1}{7}*0.049+\frac{3}{8}-\frac{7}{20}

7

1

∗0.049+

8

3

−

20

7

=\frac{1}{7}*\frac{49}{1000}+\frac{3}{8}-\frac{7}{20}=

7

1

∗

1000

49

+

8

3

−

20

7

=\frac{7}{1000}+\frac{3}{8}-\frac{7}{20}=

1000

7

+

8

3

−

20

7

=\frac{7}{1000}+\frac{3*125}{8*125}-\frac{7*50}{20*50}=

1000

7

+

8∗125

3∗125

−

20∗50

7∗50

=\frac{7}{1000}+\frac{375}{1000}-\frac{350}{1000}=

1000

7

+

1000

375

−

1000

350

=\frac{7+375-350}{1000}=

1000

7+375−350

=\frac{382-350}{1000}=

1000

382−350

=\frac{32}{1000}=

1000

32

=\frac{4}{125}=

125

4