Question

1.7*1.7*1.7-0.9*0.9*0.9/1.7*1.7+1.7*0.9+0.9*0.9

Answer 1

How are you But I don't know you questions not answer sorry

Answer 2

$\frac{1.7^{3}-0.9^{3}}{1.7^{2}+1.7\times 0.9+0.9^{2}}=0.8$.

Step-by-step explanation:

1. From identity

   $a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})$      ...1)

2. Then from equation 1)

$1.7\times 1.7\times 1.7-0.9\times 0.9\times 0.9=1.7^{3}-0.9^{3}=(1.7-0.9)(1.7^{2}+1.7\times 0.9+0.9^{2})$       ...2)

3. From question

$\frac{1.7^{3}-0.9^{3}}{1.7^{2}+1.7\times 0.9+0.9^{2}}=\frac{(1.7-0.9)(1.7^{2}+1.7\times 0.9+0.9^{2})}{(1.7^{2}+1.7\times 0.9+0.9^{2})}$    ...3)  

4. equation 3) which can written as after cancel out common term in numerator and denominator.

$\frac{1.7^{3}-0.9^{3}}{1.7^{2}+1.7\times 0.9+0.9^{2}}=(1.7-0.9)=0.8$