Math, asked by IamRahul230, 11 months ago

(((1/7^2)^-1/3)^-1/4) =7^m find the value of m

Answers

Answered by pmace
1

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Answered by seema9869
0

Answer: -1/3

Step-by-step explanation:

[{(1/(7)^2)^-2}^-1/3]^1/4 = 7ⁿ

(1/7)^1/3 = 7ⁿ (cancelling out exponents)

7^-1/3 = 7ⁿ

(Since bases are same, exponents are equal)

Therefore,

-1/3 = ⁿ

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