(((1/7^2)^-1/3)^-1/4) =7^m find the value of m
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Answer: -1/3
Step-by-step explanation:
[{(1/(7)^2)^-2}^-1/3]^1/4 = 7ⁿ
(1/7)^1/3 = 7ⁿ (cancelling out exponents)
7^-1/3 = 7ⁿ
(Since bases are same, exponents are equal)
Therefore,
-1/3 = ⁿ
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