Question

1/√7+√3-√2

rationlise it fast please

Answer 1

$\textbf{Answer:}$

$= > \frac{1}{ \sqrt{7} + \sqrt{3} - \sqrt{2} } \\ \\ = > \frac{1}{ \sqrt{7} + \sqrt{3} - \sqrt{2}} \times \\ \\ \frac{ \sqrt{7} + \sqrt{3} + \sqrt{2}}{ \sqrt{7} + \sqrt{3} + \sqrt{2}} \\ \\ = > \frac{ \sqrt{7} + \sqrt{3} + \sqrt{2} }{( \sqrt{7} + \sqrt{3}) {}^{2} - ( \sqrt{2} ) {}^{2} } \\ \\ = > \frac{ \sqrt{7} + \sqrt{3} + \sqrt{2} }{7 + 2 \sqrt{21} + 3 - 2} \\ \\ = > \frac{ \sqrt{7} + \sqrt{3} + \sqrt{2} }{8 - 2 \sqrt{21} }$

$\textbf{THANK YOU}$